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\u222bsin(x)sin(2x)dx
\u3053\u308c\u3001\u672c\u5f53\u306b\u7a4d\u5206\u306a\u3093\u3066\u3067\u304d\u308b\u306e\u304b\u3068\u601d\u3046\u304c\u3001\u306a\u3093\u3068\u304b\u3067\u304d\u308b\u3002
\u7a4d\u3092\u548c\u306b\u76f4\u3059\u516c\u5f0f\u3092\u7528\u3044\u308c\u3070\u4e00\u77ac\u3067\u3067\u304d\u308b\u304b\u3082\u3057\u308c\u306a\u3044\u304c\u3001
\u500d\u89d2\u306e\u516c\u5f0f\u3084\u52a0\u6cd5\u5b9a\u7406\u3060\u3051\u3067\u5909\u5f62\u3055\u305b\u308b\u3068
sin(x)sin(2x)=sin(3x\/2+x\/2)sin(3x\/2-x\/2)={sin(3x\/2)cos(x\/2)-cos(3x\/2)sin(x\/2)}{sin(3x\/2)cos(x\/2)+cos(3x\/2)sin(x\/2)}
=sin^2(3x\/2)cos^2(x\/2)-cos^2(3x\/2)sin^2(x\/2)
\u3053\u3053\u3067\u52a0\u6cd5\u5b9a\u7406\u3067
=(1-cos(3x))\/2 * (1+cos(x))\/2 – (1+cos(3x))\/2 * (1-cos(x))\/2
={ 1-cos(3x)+cos(x)-cos(3x)cos(x)-1-cos(3x)+cos(x)-cos(3x)cos(x) } \/4
={cos(x)-cos(3x)}\/2
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